-5≤y≤-1
no.7
a.b.c.d.e=128
a.ar.ar2.ar3.ar4 = 128
a5.r(1+2+3+4) = 27
a5.r10 = 27
ar2 = 27/5
U3 = 27/5
no.8
no.9
x2+ax-a2=0
(α4+β4)=(α2+β2)2-2(αβ)2
=[(α+β)2-2αβ]2-2(αβ)2
=[a2+2a2 ]2-2(-a2)2
=9a4-2a4
=7a4
no.10
Pembahasan Problem Set 3 - Dasar (no.6-10)
-5≤y≤-1
no.7
a.b.c.d.e=128
a.ar.ar2.ar3.ar4 = 128
a5.r(1+2+3+4) = 27
a5.r10 = 27
ar2 = 27/5
U3 = 27/5
no.8
no.9
x2+ax-a2=0
(α4+β4)=(α2+β2)2-2(αβ)2
=[(α+β)2-2αβ]2-2(αβ)2
=[a2+2a2 ]2-2(-a2)2
=9a4-2a4
=7a4
no.10